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Secondary containment capacity

Used on the ASP and CSP. The worked example below is computed by code and checked against the source.

Capacity ≥ the greater of 10% of total container volume or the largest container

Hazardous waste container storage areas under 40 CFR 264.175. Containers without free liquids are not counted.

Worked example

20 drums of 55 gal each.

max(0.10 × 1,100, 55) = 110 gal

Where it appears on the exam

Source

The formula comes from

40 CFR 264.175(b)(3)(opens ecfr.gov in a new tab)
“The containment system must have sufficient capacity to contain 10% of the volume of containers or the volume of the largest container, whichever is greater. Containers that do not contain free liquids need not be considered in this determination;”

Questions

What is the formula for secondary containment capacity?
Capacity ≥ the greater of 10% of total container volume or the largest container. Hazardous waste container storage areas under 40 CFR 264.175. Containers without free liquids are not counted.
Will this formula be given on the BCSP exam?
BCSP says the formula is included in the question whenever one is needed, unless the question is testing whether you know the formula. You can't bring a formula sheet into the exam, so learn what each formula does and when to use it.

BCSP on formulas at the exam

BCSP, What to Expect When Sitting for a BCSP Exam (item 7)(opens bcsp.org in a new tab)
“For any question requiring a mathematical formula, the formula will be included within the exam question (unless the question is specifically testing your knowledge of a formula). You will not be provided or permitted to bring a formula sheet.”

Related

Checked 2026-10-16. Spot a problem? Email hello@passcited.com.

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