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Noise TWA from dose

Used on the ASP, CSP and CHST. The worked example below is computed by code and checked against the source.

TWA = 16.61 × log10(D ÷ 100) + 90

D = dose in percent. A 100% dose is a 90 dBA TWA; a 50% dose is 85 dBA, the hearing conservation action level.

Worked example

A 150% dose (the example above).

16.61 × log10(1.5) + 90 = 92.9 dBA

The source prints this result, and our code reproduces it.

1910.95 Table A-1 lists 92.9 dBA for a 150% dose.

Run your own numbers: noise dose calculator or hearing protection NRR calculator.

Where it appears on the exam

Source

The formula comes from

29 CFR 1910.95, Appendix A(opens ecfr.gov in a new tab)
“The eight-hour time-weighted average sound level (TWA), in decibels, may be computed from the dose, in percent, by means of the formula: TWA = 16.61 log10 (D/100) + 90.”

Questions

What is the formula for noise TWA from dose?
TWA = 16.61 × log10(D ÷ 100) + 90. D = dose in percent. A 100% dose is a 90 dBA TWA; a 50% dose is 85 dBA, the hearing conservation action level.
Will this formula be given on the BCSP exam?
BCSP says the formula is included in the question whenever one is needed, unless the question is testing whether you know the formula. You can't bring a formula sheet into the exam, so learn what each formula does and when to use it.

BCSP on formulas at the exam

BCSP, What to Expect When Sitting for a BCSP Exam (item 7)(opens bcsp.org in a new tab)
“For any question requiring a mathematical formula, the formula will be included within the exam question (unless the question is specifically testing your knowledge of a formula). You will not be provided or permitted to bring a formula sheet.”

Related

Checked 2026-10-16. Spot a problem? Email hello@passcited.com.

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