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CSP Domain 6: Occupational Health and Applied Science

Domain 6 is 10% of the CSP, number 4 of 7 domains by weight. PassCited has 116 questions for it.

BCSP's CSP11 Examination Blueprint, V.2024.04.24 weights Occupational Health and Applied Science at 10% of the CSP, a 5.5-hour exam. Give it study time in proportion to its weight.

Blueprint tasks we cover in this domain

Task numbers follow the BCSP blueprint. Tasks with no public-domain source (for example ISO standards or management theory) are thin or missing in our bank, and we say so rather than invent content.

  • 6.1 Exposure measurement
  • 6.1 Measurement, sampling and control of exposures
  • 6.1 Noise
  • 6.1 Physical agents (heat, vibration)
  • 6.2 Applied science calculations
  • 6.3 Toxicology (LD50, LC50, carcinogens)
  • 6.4 Lifting
  • 6.5 Containment volumes

Topics

Regulations this domain's questions cite most

Free Domain 6 practice questions

Question 1Calculation

Air sampling shows a painter's exposure to acetone during an 8-hour shift was 4 hours at 1640 ppm, 1 hour at 793 ppm, 3 hours at 208 ppm. Using OSHA's cumulative exposure formula, what is the 8-hour equivalent exposure (E)?

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Answer: D. 997.1 ppm

E = (Ca Ta + Cb Tb + Cc Tc) ÷ 8 = (1640 x 4 + 793 x 1 + 208 x 3) ÷ 8 = 997.1 ppm. Averaging the three concentrations without weighting by time gives a different, incorrect value.

Answer D rests on

29 CFR 1910.1000(d)(1)(i)(opens ecfr.gov in a new tab)
“The cumulative exposure for an 8-hour work shift shall be computed as follows: E = (Ca Ta + Cb Tb + . . .Cn Tn) ÷ 8 Where: E is the equivalent exposure for the working shift. C is the concentration during any period of time T where the concentration remains constant. T is the duration in hours of the exposure at the concentration C.”

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Question 2

An industrial hygienist is evaluating a worker's exposure to a single contaminant with an 8-hour TWA limit of 100 ppm. The worker spent 2 hours at 150 ppm, 2 hours at 75 ppm, and 4 hours at 50 ppm. Which conclusion is correct?

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Answer: D. The 8-hour TWA is 81.25 ppm, which is below 100 ppm, so the exposure is acceptable

The standard's formula weights each concentration by its duration: (2×150 + 2×75 + 4×50) ÷ 8 = 81.25 ppm, which is less than 100 ppm, so the exposure is acceptable. A short period above 100 ppm does not by itself make the TWA unacceptable.

Answer D rests on

29 CFR 1910.1000(d)(1)(ii)(opens ecfr.gov in a new tab)
“Substituting this information in the formula, we have (2 × 150 + 2 × 75 + 4 × 50) ÷ 8 = 81.25 ppm Since 81.25 ppm is less than 100 ppm, the 8-hour time weighted average limit, the exposure is acceptable.”

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Question 3

A plant's maintenance technicians move between several buildings during a shift, and their noise levels vary widely from task to task. The safety manager must decide how to conduct exposure monitoring. Which approach does the standard require unless area sampling can be shown to give equivalent results?

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Answer: D. Representative personal sampling

When high worker mobility or significant variations in sound level make area monitoring generally inappropriate, the standard requires representative personal sampling unless the employer can show area sampling produces equivalent results. The other approaches are not the method the standard prescribes.

Answer D rests on

29 CFR 1910.95(d)(1)(ii)(opens ecfr.gov in a new tab)
“Where circumstances such as high worker mobility, significant variations in sound level, or a significant component of impulse noise make area monitoring generally inappropriate, the employer shall use representative personal sampling to comply with the monitoring requirements of this paragraph unless the employer can show that area sampling produces equivalent results.”

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